How to find the area of ​​a parallelogram if the angle is known. Area of ​​a parallelogram

Parallelogram is a quadrilateral whose sides are parallel in pairs.

In this figure, opposite sides and angles are equal to each other. The diagonals of a parallelogram intersect at one point and bisect it. Formulas for the area of ​​a parallelogram allow you to find the value through the sides, height and diagonals. A parallelogram can also be presented in special cases. They are considered a rectangle, square and rhombus.
First, let's look at an example of calculating the area of ​​a parallelogram by height and the side to which it is lowered.

This case is considered classic and does not require additional investigation. It’s better to consider the formula for calculating the area through two sides and the angle between them. The same method is used in calculations. If the sides and the angle between them are given, then the area is calculated as follows:

Suppose we are given a parallelogram with sides a = 4 cm, b = 6 cm. The angle between them is α = 30°. Let's find the area:

Area of ​​a parallelogram through diagonals


The formula for the area of ​​a parallelogram using the diagonals allows you to quickly find the value.
For calculations, you will need the size of the angle located between the diagonals.

Let's consider an example of calculating the area of ​​a parallelogram using diagonals. Let a parallelogram be given with diagonals D = 7 cm, d = 5 cm. The angle between them is α = 30°. Let's substitute the data into the formula:

An example of calculating the area of ​​a parallelogram through the diagonal gave us an excellent result - 8.75.

Knowing the formula for the area of ​​a parallelogram through the diagonal, you can solve many interesting problems. Let's look at one of them.

Task: Given a parallelogram with an area of ​​92 square meters. see Point F is located in the middle of its side BC. Let's find the area of ​​the trapezoid ADFB, which will lie in our parallelogram. First, let's draw everything we received according to the conditions.
Let's get to the solution:

According to our conditions, ah =92, and accordingly, the area of ​​our trapezoid will be equal to

Parallelogram called a quadrilateral whose opposite sides are parallel to each other. The main tasks in school on this topic are to calculate the area of ​​a parallelogram, its perimeter, height, and diagonals. The indicated values ​​and formulas for calculating them will be given below.

Properties of a parallelogram

The opposite sides of a parallelogram, as well as the opposite angles, are equal to each other:
AB=CD, BC=AD,

The diagonals of a parallelogram at the point of intersection are divided into two equal parts:

AO=OC, OB=OD.

Angles adjacent to any side (adjacent angles) add up to 180 degrees.

Each of the diagonals of a parallelogram divides it into two triangles of equal area and geometric dimensions.

Another remarkable property that is often used when solving problems is that the sum of the squares of the diagonals in a parallelogram is equal to the sum of the squares of all sides:

AC^2+BD^2=2*(AB^2+BC^2) .

The main features of parallelograms:

1. A quadrilateral whose opposite sides are parallel in pairs is a parallelogram.
2. A quadrilateral with equal opposite sides is a parallelogram.
3. A quadrilateral with equal and parallel opposite sides is a parallelogram.
4. If the diagonals of a quadrilateral at the intersection point are divided in half, then it is a parallelogram.
5. A quadrilateral whose opposite angles are equal in pairs is a parallelogram

Bisectors of a parallelogram

The bisectors of opposite angles in a parallelogram can be parallel or coincident.

Bisectors of adjacent angles (adjacent to one side) intersect at right angles (perpendicular).

Parallelogram height

Parallelogram height- this is a segment drawn from an angle perpendicular to the base. It follows from this that two heights can be drawn from each angle.

Parallelogram area formula

Area of ​​a parallelogram is equal to the product of the side and the height drawn to it. The area formula is as follows

The second formula is no less popular in calculations and is defined as follows: the area of ​​a parallelogram is equal to the product of adjacent sides and the sine of the angle between them

Based on the above formulas, you will know how to calculate the area of ​​a parallelogram.

Parallelogram perimeter

The formula for calculating the perimeter of a parallelogram is

that is, the perimeter is equal to twice the sum of the sides. Problems involving parallelograms will be discussed in adjacent materials, but for now, study the formulas. Most problems in calculating the sides and diagonals of a parallelogram are quite simple and boil down to knowledge of the theorem of sines and the Pythagorean theorem.

A parallelogram is a quadrangular figure whose opposite sides are parallel and equal in pairs. Its opposite angles are also equal, and the point of intersection of the diagonals of the parallelogram divides them in half, being at the same time the center of symmetry of the figure. Special cases of a parallelogram are geometric shapes such as square, rectangle and rhombus. The area of ​​a parallelogram can be found in various ways, depending on what initial data accompanies the formulation of the problem.


The key characteristic of a parallelogram, very often used when finding its area, is its height. The height of a parallelogram is usually called a perpendicular drawn from an arbitrary point on the opposite side to a straight segment forming that side.
  1. In the simplest case, the area of ​​a parallelogram is defined as the product of its base and its height.

    S = DC ∙ h


    where S is the area of ​​the parallelogram;
    a - base;
    h is the height drawn to the given base.

    This formula is very easy to understand and remember if you look at the following figure.

    As you can see from this image, if we cut off an imaginary triangle to the left of the parallelogram and attach it to the right, the result will be a rectangle. As you know, the area of ​​a rectangle is found by multiplying its length by its height. Only in the case of a parallelogram will the length be the base, and the height of the rectangle will be the height of the parallelogram lowered to a given side.

  2. The area of ​​a parallelogram can also be found by multiplying the lengths of two adjacent bases and the sine of the angle between them:

    S = AD∙AB∙sinα


    where AD, AB are adjacent bases forming an intersection point and an angle a between themselves;
    α is the angle between the bases AD and AB.

  3. You can also find the area of ​​a parallelogram by dividing in half the product of the lengths of the diagonals of the parallelogram by the sine of the angle between them.

    S = ½∙AC∙BD∙sinβ


    where AC, BD are the diagonals of the parallelogram;
    β is the angle between the diagonals.

  4. There is also a formula for finding the area of ​​a parallelogram through the radius of the circle inscribed in it. It is written as follows:

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Area of ​​a parallelogram. In many geometry problems related to the calculation of areas, including tasks on the Unified State Exam, formulas for the area of ​​a parallelogram and a triangle are used. There are several of them, we will look at them here.

It would be too simple to list these formulas; there is already enough of this stuff in reference books and on various websites. I would like to convey the essence - so that you do not cram them, but understand them and can easily remember them at any time. After studying the material in the article, you will understand that there is no need to learn these formulas at all. Objectively speaking, they occur so often in decisions that they remain in memory for a long time.

1. So let's look at a parallelogram. The definition reads:


Why is this so? It's simple! To show clearly what the meaning of the formula is, let’s perform some additional constructions, namely, construct the heights:

The area of ​​triangle (2) is equal to the area of ​​triangle (1) - the second sign of equality of right triangles “along the leg and hypotenuse”. Now let’s mentally “cut off” the second one and move it overlaying it on the first one - we get a rectangle, the area of ​​which will be equal to the area of ​​the original parallelogram:


The area of ​​a rectangle is known to be equal to the product of its adjacent sides. As can be seen from the sketch, one side of the resulting rectangle is equal to the side of the parallelogram, and the other is equal to the height of the parallelogram. Therefore, we obtain the formula for the area of ​​a parallelogram S = a∙h a

2. Let's continue, another formula for its area. We have:

Area of ​​a parallelogram formula

Let's denote the sides as a and b, the angle between them is γ "gamma", the height is h a. Consider a right triangle:




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